ValueError: invalid literal for int() with base 10: '' Query Bro
Solution First : -
Just for the record:
>>> int('55063.000000')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '55063.000000'
Got me here...
>>> int(float('55063.000000'))
55063
Solution Second: -
The following are totally acceptable in python:
- passing a string representation of an integer into
int - passing a string representation of a float into
float - passing a string representation of an integer into
float - passing a float into
int - passing an integer into
float
But you get a ValueError if you pass a string representation of a float into int, or a string representation of anything but an integer (including empty string). If you do want to pass a string representation of a float to an int, as @katyhuff points out above, you can convert to a float first, then to an integer:
>>> int('5')
5
>>> float('5.0')
5.0
>>> float('5')
5.0
>>> int(5.0)
5
>>> float(5)
5.0
>>> int('5.0')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '5.0'
>>> int(float('5.0'))
5